Support Board
Date/Time: Sun, 24 Nov 2024 17:44:13 +0000
LN function
View Count: 245
| [2024-05-13 12:31:25] |
| User411320 - Posts: 289 |
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Hello, I'm using LN in the spreadsheet =LN(E3-E4) where E is "last" price. I'm getting #NUM! for some values. According to the documentation that's because the number is less than or equal to 0. so my question is how do I fix that ?
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| [2024-05-13 16:58:29] |
| John - SC Support - Posts: 36238 |
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You can not fix this. You can not take the log (natural or otherwise) of a negative number. Keep in mind a Log is the power you need to raise a value to in order to get the desired number. This is why you can not take a log of a negative number. The only thing we can suggest is taking the Absolute Value of "E3 - E4" (LN(ABS(E3-E4)), but we do not know if this actually what you want. For the most reliable, advanced, and zero cost futures order routing, use the Teton service: Sierra Chart Teton Futures Order Routing |
| [2024-05-16 17:26:08] |
| User411320 - Posts: 289 |
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hello, I'm trying to do this "Ln(Close) - Ln(Close1) : Close1 is previous close", so I can normalize data. I also tried the formula you gave me but it gave me a syntax error |
| [2024-05-16 17:55:58] |
| John - SC Support - Posts: 36238 |
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The following formula works for us: =LN(ABS(E3 - E4)) You can do what you suggested with this "Ln(Close) - Ln(Close1)" as each close is a positive value. So the formula would be the following: =LN(E4) - LN(E3) For the most reliable, advanced, and zero cost futures order routing, use the Teton service: Sierra Chart Teton Futures Order Routing |
| [2024-05-18 19:34:18] |
| User411320 - Posts: 289 |
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thank you that worked
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