Support Board

if (sc.MenuEventID == r_SetEntry || sc.ExecuteKeboardShortcut == EntryKeySequence)

  sc.ReceiveKeyboardKeyEvents = 1;
  sc.ReceiveCharacterEvents = 1;
  sc.SupportKeyboardModifierStates = 1;
  
  int PressedKey = sc.KeyboardKeyEventCode;
  
  if (sc.MenuEventID == r_SetEntry || (sc.IsKeyPressed_Control && sc.IsKeyPressed_Shift && PressedKey == 69)) // E = 0x45 = 69 (Confirmed using sc.ReceiveKeyboardKeyEvents)
  {

/*=============================================================================
  *** Prepared for educational purposes only, see terms at end of code ***
  
  File: Keyboard-Test-v01a-20190307-2120.cpp
  Date last updated: 2019-03-07 2120

  NOTES:
  If a single key is pressed, it appears that one can use sc.KeyboardKeyEventCode
and the Windows Virtual Key Code number.

However, it appears that when trying to use a combination of keys, i.e. CTRL E
sc.KeyboardKeyEventCode and Windows Virtual Key Code number will NOT work.
For combinations, one must use sc.CharacterEventCode and the ASCII value.

See below for examples.
*/

#include "sierrachart.h"

SCDLLName("Keyboard Test v01a 03-07 2120 T4p DLL")
  
SCSFExport scsf_KeyboardTest01aT4p(SCStudyInterfaceRef sc)
{
  sc.GraphName = "Keyboard Test";

  sc.StudyDescription = "";

  sc.GraphRegion = 0;    

  sc.AutoLoop = 0;
    
  sc.ReceiveKeyboardKeyEvents = 1;

  sc.ReceiveCharacterEvents = 1;

  sc.SupportKeyboardModifierStates = 1;


  int PressedKey = sc.KeyboardKeyEventCode;
  int PressedChar = sc.CharacterEventCode;

  
  if ((PressedChar == 101)) // E = ASCII value of 101

  {
    SCString Message;

    Message.Format("sc.CharacterEventCode method - ASCII: E ( %d ) was pressed", PressedChar);        

    sc.AddMessageToLog(Message, 1);    
  }
  
  if ((PressedKey == 69)) // E = Windows Virtual Key value of 69

  {
    SCString Message;

    Message.Format("sc.KeyboardKeyEventCode metod - Windows Virtual Key: E ( %d ) was pressed", PressedKey);        

    sc.AddMessageToLog(Message,1);    
  }

  
  if ((sc.IsKeyPressed_Control && sc.IsKeyPressed_Shift && PressedChar == 5))

  {
    SCString Message;

    Message.Format("Control, Shift and E ( %d ) were pressed", PressedChar);        

    sc.AddMessageToLog(Message,1);    
  }

  // NOTE: The following will trigger even if you use another key in the combination.
  // i.e. When you press CTRL SHIFT E, the above if stmt triggers AND so does the one below.
  // Also note that you do not need to include sc.IsKeyPressed, only the ASCII code.
  
  if ((PressedChar == 5)) // CTRL E = ASCII value of 5

  {
    SCString Message;

    Message.Format("CTRL E ( %d ) were pressed", PressedChar);        

    sc.AddMessageToLog(Message,1);    
  }



// ****************** DISCLAIMER **********************************************
//
// This code is provided for educational purposes on an As Is, Where Is basis.
// No express or implied warranties are provided.
// There may be errors in this code, and it must not be used for live trading.
// Trading is very risky and you can lose more than you have invested.
// Past performance is not necessarily indicative of future results.
// By using any of this code, you acknowledge & agree to the above.
//
//=============================================================================
}